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Byju's Answer
Standard XII
Mathematics
Definition of Relations
Simplify(i) ...
Question
Simplify
(i)
(
10
+
√
3
)
(
2
+
√
5
)
(ii)
(
√
5
+
√
3
)
2
(iii)
(
√
13
−
√
2
)
(
√
13
+
√
12
)
(iv)
(
8
+
√
3
)
(
8
−
√
3
)
.
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Solution
(
i
)
20
+
10
√
5
+
2
√
3
+
√
15
(
i
i
)
(
a
+
b
)
2
=
a
2
+
b
2
+
2
a
b
=
5
+
3
+
2
√
15
(
i
i
i
)
(
a
−
b
)
(
a
+
b
)
=
a
2
−
b
13
+
√
126
−
√
26
−
√
24
(
v
i
)
(
a
−
b
)
(
a
+
b
)
=
a
2
−
b
2
=
64
−
3
=
61
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0
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(ii)
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Q.
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Q.
Simplify:
(i)
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-
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3
2
+
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3
+
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3
-
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(ii)
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+
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+
5
-
3
5
+
3
(iii)
7
+
3
5
3
+
5
+
7
-
3
5
3
-
5
(iv)
1
2
+
3
+
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-
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(v)
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