$S O_{2}$ passed through acidic potassium permanganate solution (purple in colour) turns it ______.

blue

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colourless

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remain same

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black

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Solution

The correct option is B colourless
Sulphur dioxide ( $S O_{2}$ ) is passed through an acidified solution of potassium permagnate ( $K M n O_{4}$ ) which is purple in colour.On doing so, sulphur dioxide being a strong reducing agent ,reduces the purple coloured solution to form a colourless solution .
$2 K M n O_{4} + 5 S O_{2} + 2 H_{2} O \to K_{2} S O_{4} + 2 M n S O_{4} + 2 H_{2} S O_{4}$
(purple) (colourless)

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An acid which can decolourise purple coloured potassium permanganate solution is :

(a) sulphuric acid (b) citric acid

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C O_{2}

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