Solve: $8\frac{2}{3}+9\frac{3}{8}$

The correct option is B $\frac{433}{24}$
Given, $8\frac{2}{3}+9\frac{3}{8}$

Could be written as,

$\frac{26}{3}+\frac{75}{8}$

LCM of 3 and 8 is 24,

= $\frac{208}{24}+\frac{225}{24}$

= $\frac{433}{24}$