Solve for $x$ and $y:$
$\left[\begin{array}{cc}-2 & 0 \\ 3 & 1\end{array}\right]\left[\begin{array}{c}-1 \\ 2 x\end{array}\right]+3\left[\begin{array}{c}-2 \\ 1\end{array}\right]=2\left[\begin{array}{l}y \\ 3\end{array}\right]$.

$$
\begin{aligned}
&{\left[\begin{array}{cc}
-2 & 0 \\
3 & 1
\end{array}\right]\left[\begin{array}{c}
-1 \\
2 x
\end{array}\right]+3\left[\begin{array}{c}
-2 \\
1
\end{array}\right]=2\left[\begin{array}{l}
y \\
3
\end{array}\right]} ~~~~~~\text{[0.5 Mark]}\\
&\Rightarrow\left[\begin{array}{c}
2+0 \\
-3+2 x
\end{array}\right]+\left[\begin{array}{c}
-6 \\
3
\end{array}\right]=\left[\begin{array}{c}
2 y \\
6
\end{array}\right] \\
&\Rightarrow\left[\begin{array}{c}
2 \\
-3+2 x
\end{array}\right]+\left[\begin{array}{c}
-6 \\
3
\end{array}\right]=\left[\begin{array}{c}
2 y \\
6
\end{array}\right] ~~~~~~~~~~\text{[0.5 Mark]}\\
&\Rightarrow\left[\begin{array}{c}
2-6 \\
-3+2 x+3
\end{array}\right]=\left[\begin{array}{c}
2 y \\
6
\end{array}\right] \\
&\Rightarrow\left[\begin{array}{c}
-4 \\
2 x
\end{array}\right]=\left[\begin{array}{c}
2 y \\
6
\end{array}\right] \\
&\Rightarrow 2 \mathrm{y}=-4 \text { and } 2 \mathrm{x}=6 \\
&\Rightarrow \mathrm{y}=-2 \text { and } \mathrm{x}=3
\end{aligned}
$$
Thus, the values of $x$ and $y$ are: $3,-2$ [1 Mark]