Solve the following equation:
$2{\tan }^{2}x+3=\frac{3}{\cos x}$

$2{\tan }^{2}x+3=\frac{3}{\cos x}$

$2({\text{sec}}^{2}x-1)+3=3\text{sec}x$

$2{\text{sec}}^{2}x-3\text{sec}x+1=0⟹\text{sec}x=1⟹x=2n\pi$