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Question

Solve the following equation:
cosx+cos4x+cos7x=0

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Solution

2cos4xcos3x+cos4x=0
cos4x(2cos3x+1)=0
So, cos4x=0,4x=(2n+1)π2,x=(2x+1)π8. and cos3x=12,3x=2nπ±π3,x=2nπ3±π9.

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