Solve the following equation:
$\frac{{0.2}^{x+0.5}}{\sqrt{5}}=\frac{(0.04{)}^x}{25}$

$\frac{{0.2}^{x+0.5}}{\sqrt{5}}=\frac{(0.04{)}^x}{25}$

$(0.2{)}^{x+0.5-2x}=5^{-1.5}$

$5^{x-0.5}=5^{-1.5}$

$\therefore x=-1$