Solve this:
The elements H, S and O give compounds H₂S, SO₂ and H₂O, respectively. H₂S contains 5.88% of S and H₂O contains 88.89% of O.
Prove that the given information explains the law of reciprocal proportions.

Dear student

The weight of oxygen in water = 88.89 g
The weight of hydrogen in water = 100-88.89 = 11.11 g
the weight of sulphur in sulphur dioxide = 50g
weight of oxygen sulphur dioxide = 100 -50 = 50g
The weight of sulphur that combines with 88.89 g of oxygen = 50/50 x 88.89 = 88.89g
The ratio between the weights of sulphur and hydrogen which combine with a fixed weight of oxygen
88.89: 11.1 = 8:1 -----1
The weight of hydrogen = 5.88g
The weight of sulphur in hydrogen sulfide = 100 - 5.88 = 94.12g
The ratio between weights of sulphur and hydrogen is 94.11: 5.89 =16:1 --------2
from the two equations 1 and 2 we get the ratios 8/1 :16/1 =8:16 = 1:2
From the answer, we are able to know that these are simple multiples of each other. hence here Law of reciprocal proportion is verified.

Regards