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Question
√4+3√20i+√4−3√20i=
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Solution
The correct option is A 6
√4+3√20i=±(3+√5i)
Similarly, √4−3√20i=±(3−√5i)Hence, the possible combinations can be : 3+√5i+3−√5i=63+√5i−3+√5i=2√5i−3−√5i+3−√5i=−2√5i−3−√5i−3+√5i=−6
Hence, option A is correct
√4+3√20i=±(3+√5i)
Similarly,
√4−3√20i=±(3−√5i)
Hence, the possible combinations can be :
3+√5i+3−√5i=6
3+√5i−3+√5i=2√5i
−3−√5i+3−√5i=−2√5i
−3−√5i−3+√5i=−6
Hence, option A is correct
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