State one relevant observation for each of the following reactions:
Action of concentrated sulphuric acid on hydrated copper sulphate.

Reaction:

1. When hydrated Copper sulphate (${\text{CuSO}}_4{\text{.5H}}_2\text{O}$) is treated in the presence of concentrated Sulphuric acid (${\text{conc. H}}_2{\text{SO}}_4$), it forms anhydrous Copper (II) sulphate ${\text{CuSO}}_4$ is formed.
2. This process is known as dehydration and ${\text{conc. H}}_2{\text{SO}}_4$ acts as a dehydrating agent.

$CuS{O}_4.5H_{2}O\left(S\right)\stackrel{conc.H_{2}S{O}_4}{\to }CuS{O}_4\left(S\right)$

blue white

Observation:

The blue coloured Copper sulphate turns into white due to dehydration.