State the order of the following surds.
(i) $\sqrt{101}$

(ii) $\sqrt[3]{5}$

(iii) $\sqrt[4]{29}$

(iv) $\sqrt[4]{7}$

(v) $\sqrt[7]{4^3}$

Surd $\sqrt[n]{a}$ is said to be of the order 'n'.

(i) The order of $\sqrt{101}$ is 2.

(ii) The order of $\sqrt[3]{5}$ is 3.

(iii) The order of $\sqrt[4]{29}$ is 4.

(iv) The order of $\sqrt[4]{7}$ is 4.

(v) We can write $\sqrt[7]{4^3}\text{as}\sqrt[7]{64}.$

The order of $\sqrt[7]{64}$ is 7.