Subtract the sum of $28$ and $- 12$ from $50$ .

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Solution

Atp, $50 - (28 - 12)$
$= 62 - 28$
$= 34$

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Subtract the sum of $\frac{2}{3}$ and $\frac{1}{2}$ from the sum of $\frac{5}{6}$ , $\frac{7}{12}$ and $\frac{4}{15}$ .

\frac{- 5}{7}

\frac{- 8}{3}

\frac{5}{2}

\frac{- 11}{12}

\frac{2}{⌊ 1} + \frac{12}{⌊ 2} + \frac{28}{⌊ 3} + \frac{50}{⌊ 4} + \frac{78}{⌊ 5} + . . . . .

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