Sulphur molecule exists as $S_{8}$ . How many moles of sulphur are present in $25.6$ grams of sulphur?

0.01

moles

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0.1

moles

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0.02

moles

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0.2

moles

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Solution

The correct option is A $0.1$ moles
$25.6$ grams $S_{8}$ ${g i v e n}$
Molar mass $= 32 \times 8 = 256 g$
Moles $= \frac{W e i g h t i n g r a m s}{M o l a r m a s s}$
$= \frac{25.6}{256}$
$= 0.1 m o l e s$

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Similar questions

Q. How many molecules and atoms of sulphur are present in 0.1 mole of S8 molecules?

How many moles of molecules and atoms of sulphur are present in 0.1 mole of $S_{8}$ ?

Q. How many molecules and atoms of sulphur are present in 0.1 moles of

S_{8}

molecule?

Q. How many grams are there in the following?

i. 2 moles of hydrogen molecule,

H_{2}

ii. 3 moles of chlorine molecule,

{Cl}_{2}

iii. 5 moles of sulphur molecule,

S_{8}

iv. 4 moles of phosphorus molecule,

P_{4}

The molecular formula for eelemental sulphur si $S_{8}$ . In a sample of 5.12 g of slphur:
(a) how many moles of sulphur are present ?
(b) HOw many molecules and atoms are present?

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Sulphur molecule exists as S8. How many moles of sulphur are present in 25.6 grams of sulphur?

The correct option is A 0.1 moles25.6 grams S8 {given}Molar mass =32×8=256gMoles =WeightingramsMolarmass=25.6256=0.1moles

Sulphur molecule exists as $S_{8}$ . How many moles of sulphur are present in $25.6$ grams of sulphur?

The correct option is A $0.1$ moles
$25.6$ grams $S_{8}$ ${g i v e n}$
Molar mass $= 32 \times 8 = 256 g$
Moles $= \frac{W e i g h t i n g r a m s}{M o l a r m a s s}$
$= \frac{25.6}{256}$
$= 0.1 m o l e s$