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Boyle's Law

I, II, III ar...

Question

$I, II, III$ are three isotherms respectively at $T_{1}, T_{2}$ and $T_{3}$ . Temperature will be in the order:

T_{1} = T_{2} = T_{3}

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T_{1} < T_{2} < T_{3}

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T_{1} > T_{2} > T_{3}

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T_{1} > T_{2} = T_{3}

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Solution

The correct option is C $T_{1} > T_{2} > T_{3}$
We know, if a horizontal line is drawn parallel to the volume axis, than at a constant pressure for every volume we get a corresponding temperature.

At constant pressure for a fixed amount of gas, volume is directly proportional to the temperature.
From graph , we know
$V_{1} > V_{2} > V_{3}$
$∴ T_{1} > T_{2} > T_{3}$

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