$\text{If}\frac{a}{5}=\frac{b}{3}=\frac{c}{18}\text{then}\frac{a+b+c}{c}\text{is}$

Q. If A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5}, then (A − B) × (B − C) is

(a) {(1, 2), (1, 5), (2, 5)}
(b) [(1, 4)]
(c) (1, 4)
(d) none of these

Q.

If A = {1, 2, 4}, B = {2, 4, 5} C = {2, 5}, then $(A-B)\times (B-C)$ is

Q. If a,b,c are the positive integers, then (a+b)(b+c)(c+a) is

Q. If $\frac{a}{6}=\frac{b}{5}=\frac{c}{11},then\frac{a+b+c}{c}$ is equal to ;

Q. The sum of ages of A, B and C together is 93 years. C is thrice as old as A and B is 18 years older than A. Then, the difference between ages B and C is?