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Hydrides of Nitrogen

The ammonia p...

Question

The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by $N i C l_{2} . 6 H_{2} O$ to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of $N i C l_{2} .6 H_{2} O$ are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is .
(Atomic weights in g $m o l^{- 1}$ : $H$ = 1, $N$ = 14, $O$ = 16, $S$ = 32, $C l$ = 35.5, $C a$ = 40, $N i$ = 59)

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Solution

$\begin{matrix} m o l e s \end{matrix} \begin{matrix} C a (O H)_{2} + 12 \end{matrix} \begin{matrix} (N H_{4})_{2} S O_{4} \frac{1584}{132} = 12 \end{matrix} \to \begin{matrix} 2 N H_{3} + 24 \end{matrix} \begin{matrix} C a S O_{4} . 2 H_{2} O (G y p s u m) \end{matrix}$
Weight of gypsum formed $= 12 \times 172 = 2064 g$
$\begin{matrix} m o l e s \end{matrix} \begin{matrix} N i C l_{2} . 6 H_{2} O + \frac{952}{238} = 4 \end{matrix} \begin{matrix} 6 N H_{3} 24 \end{matrix} \to \begin{matrix} [N i (N H_{3})_{6}] C l_{2} \frac{24}{6} = 4 \end{matrix}$
Mass of $[N i (N H_{3})_{6}] C l_{2} f o r m e d = 4 \times 232 = 928 g$
Total weight =2064 + 928 = 2992 g.

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Similar questions

N i C l_{2} .6 H_{2} O

[N i (N H_{3})_{6}] C l_{2}

100

1584

952

N i C l_{2} .6 H_{2} O

C a S O_{4} .2 H_{2} O

C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O

N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O

g m o l^{- 1}

H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59)

N i C l_{2} .6 H_{2} O

[N i (N H_{3})_{6}] C l_{2}

100

1584

952

N i C l_{2} .6 H_{2} O

C a S O_{4} .2 H_{2} O

C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O

N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O

g m o l^{- 1}

H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59)

59 g

[N = 14, H = 1, S = 32, O = 16]

[2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}]

The percentage of nitrogen by mass in ammonium sulphate is closest to (atomic masses H = 1, N = 14, O = 16, S = 32)

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