The angle between the incident ray reflected ray is $60^{o}$ . What is the angle of incidence ?

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Solution

Since the normal bisects the angle between the incident ray and reflected ray.
So, angle between the incident ray and the normal is $i = \frac{60}{2} = 30^{o}$

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Question 12

The angle between incident ray and reflected ray is $60^{\circ}$ . What is the value of angle of incidence? Given that, angle of incidence + angle of reflection= $60^{\circ}$ .

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The angle between the incident ray reflected ray is 60o. What is the angle of incidence ?

Since the normal bisects the angle between the incident ray and reflected ray. So, angle between the incident ray and the normal is i=602=30o

The angle between the incident ray reflected ray is $60^{o}$ . What is the angle of incidence ?

Since the normal bisects the angle between the incident ray and reflected ray.
So, angle between the incident ray and the normal is $i = \frac{60}{2} = 30^{o}$