The angle between the vectors A and B is - The triple product A-B-A- is equal to-A-2-B-sin-2-A-2-B-sin-cos-A-2-B-cos-2-

The correct option is D A⃗.(B⃗×A⃗)=A⃗.C⃗ Here C⃗=B⃗×A⃗ which is perpendicular to both vector A⃗ and B⃗ ∴A⃗.C⃗=0 ...

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Vector Component

The angle bet...

Question

The angle between the vectors $\to A$ and $\to B$ is $θ$ . The triple product $\to A . (\to B \times \to A)$ is equal to.

A^{2} B s i n^{2} θ

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A^{2} B s i n θ c o s θ

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A^{2} B c o s^{2} θ

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0.0

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Solution

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Similar questions

The angle between the vectors $\to A$ and $\to B$ is $θ$ . Find the value of the triple product $\to A . (\to B \times \to A)$ .

\to A

\to B

θ

\to A

(\to B \times \to A)

\to A

\to B

θ

\to A . (\to B \times \to A)

θ

| a \times b | = | a \cdot b |,

θ

θ

\to A

\to B

\frac{ˆ A \times ˆ B}{ˆ A \cdot ˆ B}

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