The angle made by the tangent to the circle x-2-y-2-8x-6y-20 - 0 at nbsp-3-1- with the positive nbsp-Direction of the x-axis is -

The correct option is D (3,1) x^2+y^2 8n+6y+20 = 0 Eqn of tgt is 3x y 4(x+3)+3(y 1)+20 = 0 → n+2y+5 = 0 M = 1/2 Tan θ = 1/2 as θ = tan^ 11/2 ...

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Reflection of a Point about a Line

The angle mad...

Question

The angle made by the tangent to the circle $x^{2} + y^{2} - 8 x + 6 y + 20$ = 0 at (3,-1) with the positive Direction of the x-axis is

$Tan^{-1}\frac{2}{3}$

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