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Question

The angular magnification of astronomical telescope of distant object is 5. If the distance between objective and eye piece is 36 cm and the final image is formed at infinity then the focal length of its objective and eye piece will be

A
fo=30cm and fe=6cm
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B
fo=.72cm and fe=3cm
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C
fo=30cm and fe=10cm
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D
fo=50cm and fe=10cm
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Solution

The correct option is A fo=30cm and fe=6cm
M=5
fo=?fe=?

L=fo+fe=36 cm

As M=fofe

Therefore, 5fe=fo

So, 6fe=36 cm

fe=6 cm

Hence fo=5×6=30 cm

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