The area of cross section of a current carrying conductor is $A_0$ and $\frac{A_0}{4}$ at section $\left(1\right)$ and $\left(2\right)$ respectively. If $v_1$ and $v_2$ are the drift velocity of region $\left(1\right)$ and $\left(2\right)$ respectively then

Q. Current is flowing through a conductor of non-uniform cross-section. If $A_1>A_2$, then the relation between the drift velocity $\left(V\right)$ and current at the two cross- sections respectively, will be

Q. The area of cross section of a conductor is $10c{m}^2$ and a current of $3A$ is flowing through it. The drift velocity of electrons is $4\times {10}^{-4}m{s}^{-1}$. What will be the new cross sectional area if we are increasing the drift velocity to $7\times {10}^{-3}m{s}^{-1}$ keeping the current flow constant?

Q. A current $I$ flows through a flat metal specimen of constant thickness and of the shape as shown in the figure. Given that $v_1,v_2$ and $v_3$ are mean drift speeds of the electron crossing the sections $P_1,P_2$ and $P_3$ respectively. Then

Q. When current $i$ is flowing through a conductor, the drift velocity is $v$. If the value of current through the conductor and its area of cross-section is doubled, then new drift velocity will be