The atomic number of an element which forms basic oxide is:

18

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17

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14

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19

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Solution

The correct option is D $19$
The atomic number of an element which forms basic oxide is $19$ . The element is potassium. $K_{2} O$ is basic in nature and $K O H$ is a strong base. Potassium is an alkali metal and all alkali metal oxides are basic in nature.

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Similar questions

The element which forms a basic oxide has the atomic number of :

(a) 18 (b) 17 (c) 14 (d) 19

The atomic number of an element Y is 17. The number of electrons in its ion $Y^{-}$ will be
(a) 17 (b) 18 (c) 19 (d) 20

X

17

Y

20

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