The atomic number of an element X is 13.What will be the number of electrons in its ion $X^{34}$

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Solution

If the atomic number of an element X is $13$ .The number of electrons in its ion $x^{3 +}$ will be 10. This is because $x^{3 +}$ is a positively charged cation. An atom loses electrons from its valence shell and becomes positively charged ion called cation. Here, Atom $X$ loses $3$ electrons and acquires $3 +$ charge. therefore the number of electrons lost will be $3$ . and the number of electrons in its ion $x^{3 +}$ will be $10$ .

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