You visited us 1 times! Enjoying our articles? Unlock Full Access!

Acceleration Due to Gravity

The average v...

Question

The average value of acceleration due to gravity on the surface of the earth is equal to :

9.8 ms

^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9.8 ms

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

19.6 ms

^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.8 s

^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 9.8 ms $^{- 2}$
Acceleration due to the gravity at earth $= g = \frac{G M}{R^{2}}$
Where G=Gravitational constant $= 6.673 \times 10^{- 11}$
M=Mass of earth $= 5.972 \times 10^{24} k g$ and
R=Radius of earth $= 6.371 \times 10^{6} m$

Putting these value in the above formula, we will get $g = 9.8 m / s^{2}$

Hence correct answer is option $A$

Suggest Corrections

Similar questions

80

9.8 m / s^{2}

9.8 m s^{- 2}

4.9 m s^{- 2}

= 6.4 \times 10^{6} m

9.8 {ms}^{- 2}

4.9 {ms}^{- 2}

= 6.4 \times 10^{6} m

6.0 \times 10^{24} k g

6.4 \times 10^{6} m

G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}

Join BYJU'S Learning Program