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Question

The bob of a simple pendulum (mass m and length l) dropped from a horizontal position strikes a block of the same mass elastically placed on a horizontal frictionless table. The K.E. of the block will be

A
2 mgl
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B
mgl/2
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C
mgl
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D
0
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Solution

The correct option is C mgl

P.E. of bob at point A = mgl
This amount of energy will be converted into kinetic energy
K.E. of bob at point B = mgl


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