wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The centre, one vertex and one focus of a hyperbola are (1,−1) , (5,−1) , (6,−1).

The equation of its directrix are:

A
5x−21=0,5x+11=0
loader
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5x+4=0, x+1=0
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5x−7=0,5x−19=0
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5x−17=0,5x−6=0
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5x−21=0,5x+11=0
Centre is (1,−1)
Vertex is (5,−1)
Focus is (6,−1)
Since axis of hyperbola is parallel to x.axis
distance between center and vertex is a =4
distance between center and focus is ae=5
∴e=54
Now coming to general equation of directrices with centre at (0,0) is x=ae
But in our case center of hyperbola is shifted ie (1,−1)
equation of directrices will be x−1=aeandx−1=−ae
Substitute the value of a and e
We have
5x−21=0and5x+11=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Extrema
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon
footer-image