The circumference of the base of a cylindrical vessel is $132cm$ and its height is $25cm$. How many litres of water can it hold? ($1000{cm}^3=1l$)

The correct option is B $34.65l$
Let the base radius of the cylindrical vessel be $r$ cm.

Then, circumference of the base of the cylindrical vessel$=2\pi r$ $cm$

According to the question, $2\pi r=132$
$\Rightarrow 2\times \frac{22}{7}\times r=132$
$\Rightarrow$ $r=\frac{132\times 7}{2\times 22}=21cm$
Height of the cylindrical vessel, $h=25cm$
$\therefore$ Capacity of the cylindrical vessel
$=\pi r^{2}h=\frac{22}{7}\times {\left(21\right)}^2\times \left(25\right){cm}^3$
$=34650{cm}^3=\frac{34650}{1000}l=34.65l$
Hence, the cylindrical vessel can hold $34.65l$ of water.