The closest distance of approach of an alpha particle travelling with a velocity ‘v’ towards $A{l}_{13}$ nucleus is ‘d’. The closest distance of approach of an alpha particle travelling with velocity ‘4v’ towards $F{e}_{26}$ nucleus is

Q. The closest distance of approach of an alpha particle travelling with a velocity ‘v’ towards $A{l}_{13}$ nucleus is ‘d’. The closest distance of approach of an alpha particle travelling with velocity ‘4v’ towards $F{e}_{26}$ nucleus is

Q. The closest distance of approach of an $\alpha -$ particle travelling with a velocity $v$ towards $\text{Al}(Z=13)$ nucleus is $d$. The closest distance of approach of an $\alpha -$particle travelling with velocity $4v$ towards $\text{Fe}(Z=26)$ nucleus is-

Q. The closest distance of approach of an $\alpha$ - particle travelling with a velocity $v$ towards a stationary nucleus is $d$. For the closest distance to become $\frac{d}{2}$ towards a stationary nucleus of double the charge, the velocity of projection of the $\alpha$- particle has to be

Q. The distance of closest approach of an $\alpha$- particle fired towards a nucleus with momentum $p$,is $r$. The distance of closest approach when the momentum of $\alpha$-particle is $2p$ is

Q. The distance of closest approach of an alpha-particle fired towards a nucleus with momentum p is r. If the momentum of the alpha-particle is 2p, the corresponding distance of closest approach is :