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Question

The condition for erythroblastosis foetalis to occur is


A

Rh -ve mother and Rh +ve baby

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B

Rh -ve mother and Rh -ve baby

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C

Rh +ve mother and Rh -ve baby

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D

Rh +ve mother and Rh +ve baby

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Solution

The correct option is A

Rh -ve mother and Rh +ve baby


The correct option is A

Explanation for correct option:

  1. Erythroblastosis fetalis results from Rh incompatibility, which may develop if a woman with Rh -ve blood conceives a fetus with Rh +ve blood.
  2. At the time of delivery, some blood cells of the baby usually enter the mother’s bloodstream.
  3. The mother’s immune system will produce antibodies against the Rh antigen, which can attack the fetal RBCs having the Rh factor during the next pregnancy.

Explanation for incorrect options:

Option B:

This is not the perfect condition for erythroblastosis fetalis.

Option C:

This is not the perfect condition for erythroblastosis fetalis.

Option D:

This is not the perfect condition for erythroblastosis fetalis.

Final Answer: The condition for erythroblastosis fetalis to occur is Rh -ve mother and Rh +ve baby.


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