The condition to be imposed on β so that (0,β) lies on or inside the triangle having sides y + 3x + 2 = 0, 3y – 2x – 5 = 0 and 4y + x – 14 = 0 is
A
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B
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C
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D
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Solution
The correct option is C Clearly point 0,β lies on y-axis. Drawing the graph of the three straight lines, we see that q≡(0,72)andP≡(0,53) Therefore, the point 0,β lies on or inside δ ABC, when 53≤β≤72