The correct order of ionic radii for the ions, $P^{3 -}, S^{2 -}, C a^{2 +}, K^{+}, C l^{-}$ is

K^{+} > C a^{2 +} > P^{3 -} > S^{2 -} > C l^{-}

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P^{3 -} > S^{2 -} > C l^{-} > C a^{2 +} > K^{+}

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P^{3 -} > S^{2 -} > C l^{-} > K^{+} > C a^{2 +}

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C l^{-} > S^{2 -} > P^{3 -} > C a^{2 +} > K^{+}

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Solution

The correct option is C $P^{3 -} > S^{2 -} > C l^{-} > K^{+} > C a^{2 +}$
For isoelectronic species, as nuclear charge increases radius decreases.

Greater the positive charge, lesser the size of ion. Greater the negative charge, larger the size of ion.

$∴$ $P^{3 -} > S^{2 -} > C l^{-} > K^{+} > C a^{2 +}$

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The correct order of ionic size of the species $K^{+}, C l^{-}, C a^{2 +}$ and $S^{2 -}$ is:

S^{2 -}, K^{+}, C a^{2 +}, C l^{-}

K^{+}, C l^{-}, S^{2 -}, C a^{2 +}

K^{+}, S^{2 -}, C l^{-}

C a^{2 +}

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