The correct order of melting point of 3d transition metals is

T i < V < C r < M n < F e < C u

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T i < V < C r > M n < F e < C u

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T i < V < C r > M n < F e > C u

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T i < V > C r < M n < F e > C u

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Solution

The correct option is C $T i < V < C r > M n < F e > C u$
Melting point of transition metal is high because of the involvement of greater number of electrons from $(n - 1) d$ in addition to the $n s$ electrons in the interatomic metallic bonding.
Generally, greater the number of unpaired electrons, higher is the melting point.
Thus, melting point of 3d metals rise to a maximum at d5 (except for anomalous values of Mn) and then, fall regularly as the atomic number increases.
In 3d series, Mn has the least melting point.
Thus, the correct order of melting point of 3d series is
$T i < V < C r > M n < F e > C o > N i > C u$

Hence, option (c) is correct.

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