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Question

The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has a smaller ionic radius. Choose the correct statement(s).


A

The empirical formula of the compound is MX

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B

The cation M and anion X have different coordination geometries

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C

The ratio of M-X bond length to the cubic unit cell edge length is 0.866

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D

The ratio of the ionic radii of cation M to anion X is 0.414.

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Solution

The correct option is C

The ratio of M-X bond length to the cubic unit cell edge length is 0.866


The correct options are (A) and (C):

Explanation for the correct answers:

Option (A):The empirical formula of the compound is MX:

  1. As the structure in the figure is of Body centered cubic (B.C.C).
  2. The M is present at the center.
  3. So, No. of M atom per unit cell = 2×12=1.
  4. No. of Xatom per unit cell = 4×14=1
  5. Hence, the empirical formula would be = MX

(C): The ratio of M-X bond length to the cubic unit cell edge length is 0.866.

  1. M-X bond length would be : a22+a22
  2. So, the bond length : a=14+12
  3. Hence, M-Xbondlengtha(edgelength)=32=0.866

Explanation for the incorrect answers:

(B): The cation M and anion X have different coordination geometries.

  1. As the structure in the figure is of B.C.C
  2. So, ther+r1=0.732(cationpresentincubicalvoid)
  3. Hence, Coordination number of cation M= 8 and that of anion X= 8.

Option (D): The ratio of the ionic radii of cation M to anion X is 0.414.

  1. Because the structure is of B.C.C
  2. So, rx-+rm-=32a
  3. 0.732rm+rx-1

Hence it would be greater than 0.414.

Therefore, the correct options are

(A): The empirical formula of the compound is MX:

(C): The ratio of M-X bond length to the cubic unit cell edge length is 0.866.


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