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Question

The density of an equilibrium mixture of N2O4 and NO2 at 101.32 KPa is 3.62 g dm3 at 288 K and 1.84 g dm3 at 348 K.


What is the heat of the reaction for the following reaction?

N2O42NO2(g)

A
ΔrH=37.29 kJ mol1.
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B
ΔrH=75.68 kJ mol1.
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C
ΔrH=95.7 kJ mol1.
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D
ΔrH=151.3 kJ mol1.
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Solution

The correct option is B ΔrH=75.68 kJ mol1.
At 288 K, Mavg.=3.62×0.0821×2881
92Mavg.=1+αKP1=4α21α2
Similarly at 348K,M/avg.=1.84×0.0821×3481
92Mavg=1+αKP2=4α21α2
logKP2KP1=ΔHo2.303R[12881348]
so,
ΔrH=75.68kJmol1

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