The density of water is $1gm/ml$. The number of molecules present in $1litre$ of water $is$

The correct option is D

55.55 × 6.023 × 1023

$1lit.ofwater$ = $1000g$

No. of molecules = $\frac{W_t}{GM.W_t}\times n$

= $\frac{1000}{18}\times N$ = $55.55\times 6.023\times {10}^{23}$