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Molecular Orbitals of Carbon

The differenc...

Question

The difference between bond orders of $C O$ and $N O^{+} is \frac{x}{2}$ where x is (Round off to the Nearest Integer)

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Solution

Bond order of $C O = 3$
$σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} π 2 p_{y}^{2}$
$B . O . = \frac{10 - 4}{2} = 3$
$N O^{+} :$
$B . O . = \frac{8 - 2}{2} = 3$
Difference = 3 - 3 = 0

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