The difference in number of crystalline water molecules in a molecule of gypsum and a molecule of plaster of Paris is

\frac{5}{2}

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2

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\frac{1}{2}

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\frac{3}{2}

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Solution

The correct option is D $\frac{3}{2}$
Gypsum is calcium sulfate dihydrate.
Plaster of Paris is calcium sulfate hemihydrate
The difference in number of crystalline water molecules in a molecule of gypsum and a molecule of plaster of Paris is $2 - \frac{1}{2} = \frac{3}{2}$ .

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