The difference of molecules of water in gypsum and plaster of paris is:
(correct answer +1, wrong answer -0.25)

\frac{5}{2}

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2

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\frac{3}{2}

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\frac{1}{2}

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Solution

The correct option is C $\frac{3}{2}$
Formula of plaster of paris = $C a S O_{4} . \frac{1}{2} H_{2} O$
Formula of gypsum= $C a S O_{4} .2 H_{2} O$
Difference of water molecules in gypsum and plaster of paris is $C a S O_{4} .2 H_{2} O - C a S O_{4} . \frac{1}{2} H_{2} O = 2 - \frac{1}{2} = \frac{3}{2}$

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