The digits of the number 122311 are arranged in all possible ways. The number of all different number greater than 3,00,000 are

The correct option is C 10
Given, Number is $122311$
The number of all different number should be greater than $3,00,000$
$\therefore$ 1st digit will be fixed that is 3 and rest 5 digits can be arranged in $5!$ ways and 1 is repeated trice so divide by $3!$ and 2 is repeated twice so divide be $2!$
$\therefore$ the no of ways are $\frac{5!}{2!3!}=10$
Hence option C is correct