The displacement-time graph for the two particles A and B are straight lines inclined at angles of $30^{0}$ and $45^{0}$ with the time axis. What is the ratio of velocities $v_{A} . v_{B}$ ?.

1: 3^1/2

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3^1/2 :1

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Solution

The correct option is A 1: 3^1/2
Velocity $= \frac{d i s p l a c e m e n t}{t i m e}$
$V_{A} = tan 30^{\circ}$
$V_{B} = tan 45^{\circ}$
$\frac{V_{A}}{V_{B}} = \frac{tan 30^{\circ}}{tan 45^{\circ}} = \frac{1}{\sqrt{3}}$

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The displacement-time graph for the two particles A and B are straight lines inclined at angles of 300 and 450 with the time axis. What is the ratio of velocities vA.vB?.

The correct option is A 1: 3^1/2Velocity =displacementtimeVA=tan30∘VB=tan45∘VAVB=tan30∘tan45∘=1√3

The displacement-time graph for the two particles A and B are straight lines inclined at angles of $30^{0}$ and $45^{0}$ with the time axis. What is the ratio of velocities $v_{A} . v_{B}$ ?.

The correct option is A 1: 3^1/2
Velocity $= \frac{d i s p l a c e m e n t}{t i m e}$
$V_{A} = tan 30^{\circ}$
$V_{B} = tan 45^{\circ}$
$\frac{V_{A}}{V_{B}} = \frac{tan 30^{\circ}}{tan 45^{\circ}} = \frac{1}{\sqrt{3}}$