The distance of the point $(-3,4)$ from the origin is?

Determine the distance.

The center of the coordinate system is called the origin. The axes intersect when both $x$ and $y$ are zero. The coordinates of the origin are $(0,0)$.

The formula of distance: $Dis\tan ce=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

point:$(-3,4)=(x_1,y_1)$

origin:$(0,0)=(x_2,y_2)or(x,y)$

Calculate the distance:

$$\begin{gathered} Dis\tan ce=\sqrt{{(0-(-3\left)\right)}^2+{(0-4)}^2} \\ =\sqrt{{\left(3\right)}^2+{(-4)}^2} \\ =\sqrt{9+16} \\ =\sqrt{25} \\ =5\mathrm{unit} \end{gathered}$$

Hence, the distance of the point $(-3,4)$ from the origin is $\mathbf{5}\mathbf{}\mathbf{unit}$.