The electron distribution in an Aluminum atom is

The correct option is A

$2,8,3$

The correct option is (A):

Explanation of the correct option:

1. The atomic number of an aluminum atom is $13$
2. According to Bohr and Bury's scheme maximum number of electrons that can be accommodated in a given shell is given by $2{\mathrm{n}}^2$
3. Thus in an aluminum atom the first(K-shell) has $2$electrons, the second(L-shell) has $8$electrons and the third (M-shell) has $3$electrons.
4. Hence the electronic configuration of the aluminum atom is

K L M

$2$ $8$ $3$

Hence the electron distribution in an Aluminum atom is $2,8,3$.