The electronic configuration of four elements L, P, Q and R are given in brackets $(1s^2,2s^{2}2p^4);Q(1s^2,2s^{2}2p^6,3s^{2}3p^5),p(1s^2,2s^{2}2p^6,3s^1);R(1s^{2}2s^{6}2p^6,3s^2)$. The formulae of ionic compounds that can be formed between these elements are

Q. Electronic configuration of some elements are given below:
$L:1s^{2}2s^{2}2p^4$
$Q:1s^{2}2s^{2}2p^{6}3s^{2}3p^5$
$P:1s^{2}2s^{2}2p^6,3s^1$
$R:1s^{2}2s^{2}2p^{6}3s^2$
The ionic compound that can be formed by these elements are:

Q. The electronic configuration of four element $L,P,Q$ and $R$ are given in brackets
$L(l{s}^2,2S^2,2p^4);P(l{s}^2,2s^2,2P^6,3s^1)$
$Q(l{s}^2,2s^{2}2P^6,3s^{2}3p^5)$$R(l{s}^2,2s^{2}2P^6,3s^2)$
The formulae of ionic compounds that can be formed between these elements are:

Q. The electronics configuration of four element $L,P,Q$ and $R$ are given in brackets $L\left(1s^2,2s^2,2p^4\right);$ $Q\left(1s^2,2s^2,2p^6,3s^2,3p^5\right);$ $P\left(1s^2,2s^2,2p^6,3s^1\right);$ $R\left(1s^2,2s^2,2p^6,3s^2\right);$

Q. Sub-shell electronic configuration of elements P, Q and R is given.
[P, Q and R are imaginary symbols]
P $=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^1$,
Q $=1s^{2}2s^{2}2p^{6}3s^{2}3p^5$,
R $=1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}4s^{2}3d^1$
(a) One of these electronic configurations given above is wrong. Which is the element?
(b) Out of P, Q and R which has the highest electronegativity?
(c) Can P and Q join to form an ionic compound? Justify your answer.

Q.

In the figure, PQRS is a parallelogram with PQ = 16 cm and QR = 10 cm. L is a point Q on PR such that RL: LP = 2:3. QL produced meets RS at M and PS produced at N. Find the lengths of PN and RM.