The electronic configuration of the outermost orbit in the case of alkaline earth metals is :

n s^{2}

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n s^{2} n p^{1}

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n s^{1}

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n s^{2} n p^{4}

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Solution

The correct option is A $n s^{2}$
As there arte two electrons are present in outer most orbital so its general outer electronic configuration is $n s^{2}$ .
Hence option A is corrcet.

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Similar questions

The correct electronic configuration of an alkaline earth metals can be:

(a) How do alkaline earth metals occur in nature ?

(b) Write the electronic configuration of the first two alkaline earth metals.

$n s^{1}$ electronic configuration is not present in:

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