The energy associated with the first orbit in the hydrogen atom is –2.18 × ${10}^{–18}$ J $ato{m}^{–1}$ . What is the energy associated with the fifth orbit?

Calculate the radius of Bohr’s fifth orbit for hydrogen atom.

Energy associated with the fifth orbit of hydrogen atom is calculated as:
$E_5=\frac{-(2.18\times {10}^{-18})}{(5{)}^2}=\frac{-2.18\times {10}^{-18}}{25}{E}_5=-8.72\times {10}^{-20}J$

Radius of Bohr’s $n^{th}$ orbit for hydrogen atom is given by, $r_n=\left(0.0529nm\right)n^2$
For, n = 5
$r_5=\left(0.0529nm\right)(5{)}^2$
$r_5=1.3225nm$