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Rotational EMF

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Question

The figure shows four situations ill which charged particles are at equal distances from the origin. If $E_{1}, E_{2}, E_{3}$ and $E_{4}$ be the magnitude of the net electric fields at the origin in four situations $(i), (i i), (i i i)$ and $(i v)$ respectively, then

A

E_{1} = E_{2} = E_{3} = E_{4}

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B

E_{1} = E_{2} > E_{3} > E_{4}

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C

E_{1} < E_{2} < E_{3} = E_{4}

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D

E_{1} > E_{2} = E_{3} < E_{4}

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Solution

The correct option is A $E_{1} = E_{2} = E_{3} = E_{4}$ .
X axis - In each case The field is equivalent to a field due to a charge of 5q placed to the left of the origin ( On interchanging the positions of a charge with respect to origin , the direction of field is reversed.On changing the sign , direction is again reversed.)
Similarly the field along Y axis is also same

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