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Compound Microscope

The focal len...

Question

The focal lengths of the objective and eye-lens of a microscope are 1 cm and 5 cm respectively. If the magnifying power for the relaxed eye is 45, then the length of the tube is

A

30 cm

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B

25 cm

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C

15 cm

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D

12 cm

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Solution

The correct option is C 15 cm
Given that $f_{0} = 1 c m, f_{e} = 5 c m, m_{\infty} = 45$
By using $m_{\infty} = \frac{(L_{\infty} - f_{0} - f_{e})}{f_{0} f_{e}} \Rightarrow 45 = \frac{(L_{\infty} - 1 - 5) \times 25}{1 \times 5} \Rightarrow L_{\infty} = 15 c m$

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