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Question

The following data are obtained during orthogonal machining with Merchants theory.

Ultimate shear strength of work material = 600 MPa,
Rake angle of the tool =6,
Coefficient of friction at chip tool interface =0.2,
Feed and depth of cut = 0.2 mm/rev and 3 mm respectively. Taylor's tool life equation is V.T0.4=100.

The power required during machining operation is

A
414 W
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B
572 W
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C
2117 W
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D
2932 W
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Solution

The correct option is A 414 W
μ=0.2,α=6,

n=0.4,C=100

τultimate=600 MPa

f=0.2 mm/rev

d=3 mm

Vopt=C[n1nLmCg]n

=100⎢ ⎢ ⎢0.40.6756015⎥ ⎥ ⎥0.4

=31.46 m/min=31.5 m/min

t1=0.2 mm,b=3 mm,

ϕ=90+αβ2

ϕ=90+611.32=42.34

600 N/mm2=Fst1sinϕ×b

Fs=534.5 N

Fs=Fccos(βα)×cos(ϕ+βα)

534.5×cos(11.36)cos(42.34+11.36)=Fc

Fc=789.88 N790 N

P=Fc×Vc

W=790×31.560

P=W=414.68 W

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