The following data was obtained on performing an experiment for determining the percentage of water absorbed by raisins:

Mass of water in the beaker = 50 g

Mass of dry raisins = 20 g

Mass of raisins after soaking in water = 30 g

Mass of water left in the beaker after the experiment = 40 g

The percentage of water absorbed by raisins will be:

(1) 10%
(2) 25%
(3) 45%
(4) 50%

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Solution

The precentage of water absorbed is calculated as -

$\frac{Final weight - Initial weight}{Initial weight} \times 100$

$\frac{30 - 20}{20} \times 100 = \frac{1000}{20} = 50 %$

Hence, the correct answer is option 4.

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Similar questions

While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:

Mass of water in the beaker = 40 g

Mass of raisins before soaking = 5 g

Mass of raisins after soaking for 2 hours = 8 g

Mass of water left in the beaker after the experiment = 35 g

The percentage of water absorbed by raisins is:

Dry raisins were soaked in water for 2 hours, to determine the percentage of water absorbed by raisins. Before final weighing of swollen raisins, the extra water left on the surface of soaked raisins was removed by:

Q. A student soaked 5 g of raisins in beaker (A) containing 25 mL of ice-chilled water and another 5 g of raisins in beaker (B) containing 25 mL of tap water at room temperature. After one hour the student observed that:
(1) water absorbed by raisins in beaker (A) was more than that absorbed by raisins of beaker (B).
(2) water absorbed by raisins in beaker (B) was more than that absorbed by raisins of beaker (A).
(3) the amount of water absorbed by the raisins of both beakers (A) and (B) was equal.
(4) no water was absorbed by raisins in either of the beakers (A) and (B).

To determine the percentage of water absorbed by raisins, raisins are soaked in water for:

Q. a student recorded the mass of dry raisins is 6.0 g and mass of raisins after soaking them in water in 10.5 g. calculate the percentage of water absorbed by raisins.

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Mass of water in the beaker	=	50 g
Mass of dry raisins	=	20 g
Mass of raisins after soaking in water	=	30 g
Mass of water left in the beaker after the experiment	=	40 g

The precentage of water absorbed is calculated as - Final weight-Initial weightInitial weight×100 30 -2020 ×100 = 100020 = 50% Hence, the correct answer is option 4.

The precentage of water absorbed is calculated as -

$\frac{Final weight - Initial weight}{Initial weight} \times 100$

$\frac{30 - 20}{20} \times 100 = \frac{1000}{20} = 50 %$

Hence, the correct answer is option 4.