The freezing point of a solution containing 28-335 cm-3 of ethylene glycol in 50 g water is found to be -34- C- Assuming ideal behaviour- calculate the density of ethylene glycol- K-f for water 1-86 K kg mol-1-

W_ethylene glycol = nbsp; M_2×Δ T_f× W_water/1000× k_f = 62× 34× 50/1000×1.86=56.67 g d=W/V=56.67/28.335=2 ...

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The freezing point of a solution containing 28.335 $c m^{3}$ of ethylene glycol in 50 g water is found to be $- 34^{\circ}$ C. Assuming ideal behaviour, calculate the density of ethylene glycol. $K_{f}$ for water 1.86 K kg $m o l^{- 1}$ .___

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50 {cm}^{3}

50 g

- 34^{\circ} C

K_{f}

= 1.86 {K kg mol}^{- 1}

- 34^{\circ} C

(K_{f} f o r w a t e r = 1.86 K k g m o l^{-} 1)

- 34^{\circ} C

(K_{f} f o r w a t e r = 1.86 K k g m o l^{-} 1)

50 c m^{3}

- 4^{o} C

(K_{f}

= 1.86 K k g m o l^{- 1}

50 {cm}^{3}

50 g

{g/cm}^{3}

(K_{f} for water = 1.86 {K Kg mol}^{- 1})

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